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2x^2=10^6
We move all terms to the left:
2x^2-(10^6)=0
We add all the numbers together, and all the variables
2x^2-1000000=0
a = 2; b = 0; c = -1000000;
Δ = b2-4ac
Δ = 02-4·2·(-1000000)
Δ = 8000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8000000}=\sqrt{4000000*2}=\sqrt{4000000}*\sqrt{2}=2000\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2000\sqrt{2}}{2*2}=\frac{0-2000\sqrt{2}}{4} =-\frac{2000\sqrt{2}}{4} =-500\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2000\sqrt{2}}{2*2}=\frac{0+2000\sqrt{2}}{4} =\frac{2000\sqrt{2}}{4} =500\sqrt{2} $
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